tag:blogger.com,1999:blog-2248764601940114006.post1222606115352225575..comments2023-12-19T07:33:13.133-06:00Comments on Cleveland Baseball Cards: How Many Packs Does It Take To Make A Set? #TheHobby #Math #MyHeadHurts--Davidhttp://www.blogger.com/profile/03884046413767054746noreply@blogger.comBlogger4125tag:blogger.com,1999:blog-2248764601940114006.post-38079425309478947472017-04-13T16:59:31.709-05:002017-04-13T16:59:31.709-05:00Hahaha, actually, that was the conclusion drawn in...Hahaha, actually, that was the conclusion drawn in most of the scenarios I found!--Davidhttps://www.blogger.com/profile/03884046413767054746noreply@blogger.comtag:blogger.com,1999:blog-2248764601940114006.post-27092536854278857792017-04-11T21:22:29.411-05:002017-04-11T21:22:29.411-05:00An interesting problem professor. My answer. Jus...An interesting problem professor. My answer. Just buy a complete set. It's cheaper and a lot less work. I know. I'm kidding.Hackenbushhttps://www.blogger.com/profile/15507810776309048794noreply@blogger.comtag:blogger.com,1999:blog-2248764601940114006.post-21333728303984398432017-04-11T21:19:21.969-05:002017-04-11T21:19:21.969-05:00That is very cool! Yeah, the problem is that older...That is very cool! Yeah, the problem is that older packs could have two dupes in my experience, but not usually more than that. Notbsure how that affects things. Hahah!--Davidhttps://www.blogger.com/profile/03884046413767054746noreply@blogger.comtag:blogger.com,1999:blog-2248764601940114006.post-47585962462598968782017-04-11T17:05:11.247-05:002017-04-11T17:05:11.247-05:00I wrote a draft of a post on this a long time ago ...I wrote a draft of a post on this a long time ago and never finished it, inspired by the 2009 Google Code Jam.<br /><br />https://code.google.com/codejam/contest/188266/dashboard#s=a&a=2 (That should link to the "Contest Analysis" of Problem C)<br /><br />That one, again, assumes no duplicates in each pack. But, each pack is not related to each other pack, the way packs within a box usually contain different cards, assuming decent collation. <br /><br />If you allow for any combination of duplicates, like the possibility all 12 cards in a pack are the same Bip Roberts card, it just devolves to the coupon collector problem you mentioned, divided by the number of cards per pack.Wilsonhttps://www.blogger.com/profile/07885481981559170900noreply@blogger.com